x^(2/5)-x^(1/5)-20=0

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Solution for x^(2/5)-x^(1/5)-20=0 equation: 


x in (-oo:+oo)

x^(2/5)-x^(1/5)-20 = 0

t_1 = x^(1/5)

1*t_1^2-1*t_1^1-20 = 0

t_1^2-t_1-20 = 0

DELTA = (-1)^2-(-20*1*4)

DELTA = 81

DELTA > 0

t_1 = (81^(1/2)+1)/(1*2) or t_1 = (1-81^(1/2))/(1*2)

t_1 = 5 or t_1 = -4

t_1 = -4

x^(1/5)+4 = 0

1*x^(1/5) = -4 // : 1

x^(1/5) = -4

( -4 < 0 i 1/5 in (0:1) ) => x należy do O

t_1 = 5

x^(1/5)-5 = 0

1*x^(1/5) = 5 // : 1

x^(1/5) = 5

x^(1/5) = 5 // ^ 5

x = 3125

x = 3125

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